13(4-5x)+3x=40

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Solution for 13(4-5x)+3x=40 equation: 



13(4-5x)+3x=40

We move all terms to the left:

13(4-5x)+3x-(40)=0

We add all the numbers together, and all the variables

13(-5x+4)+3x-40=0

We add all the numbers together, and all the variables

3x+13(-5x+4)-40=0

We multiply parentheses

3x-65x+52-40=0

We add all the numbers together, and all the variables

-62x+12=0

We move all terms containing x to the left, all other terms to the right

-62x=-12

x=-12/-62

x=6/31

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