13(4-3x)-16(2x-3)=9(4x+6)-25(3x+2)

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Solution for 13(4-3x)-16(2x-3)=9(4x+6)-25(3x+2) equation:



13(4-3x)-16(2x-3)=9(4x+6)-25(3x+2)
We move all terms to the left:
13(4-3x)-16(2x-3)-(9(4x+6)-25(3x+2))=0
We add all the numbers together, and all the variables
13(-3x+4)-16(2x-3)-(9(4x+6)-25(3x+2))=0
We multiply parentheses
-39x-32x-(9(4x+6)-25(3x+2))+52+48=0
We calculate terms in parentheses: -(9(4x+6)-25(3x+2)), so:
9(4x+6)-25(3x+2)
We multiply parentheses
36x-75x+54-50
We add all the numbers together, and all the variables
-39x+4
Back to the equation:
-(-39x+4)
We add all the numbers together, and all the variables
-71x-(-39x+4)+100=0
We get rid of parentheses
-71x+39x-4+100=0
We add all the numbers together, and all the variables
-32x+96=0
We move all terms containing x to the left, all other terms to the right
-32x=-96
x=-96/-32
x=+3

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