13(2x)x20=6(5x+2)

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Solution for 13(2x)x20=6(5x+2) equation: 



13(2x)x20=6(5x+2)

We move all terms to the left:

13(2x)x20-(6(5x+2))=0



We calculate terms in parentheses: -(6(5x+2)), so:

6(5x+2)

We multiply parentheses

30x+12

Back to the equation:

-(30x+12)



We get rid of parentheses

132xx20-30x-12=0

We add all the numbers together, and all the variables

-30x+132xx20-12=0

We move all terms containing x to the left, all other terms to the right

-30x+132xx20=12

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