12z=4z-48

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Solution for 12z=4z-48 equation: 



12z=4z-48

We move all terms to the left:

12z-(4z-48)=0

We get rid of parentheses

12z-4z+48=0

We add all the numbers together, and all the variables

8z+48=0

We move all terms containing z to the left, all other terms to the right

8z=-48

z=-48/8

z=-6

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