12z=3(10-z)

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Solution for 12z=3(10-z) equation: 



12z=3(10-z)

We move all terms to the left:

12z-(3(10-z))=0

We add all the numbers together, and all the variables

12z-(3(-1z+10))=0



We calculate terms in parentheses: -(3(-1z+10)), so:

3(-1z+10)

We multiply parentheses

-3z+30

Back to the equation:

-(-3z+30)



We get rid of parentheses

12z+3z-30=0

We add all the numbers together, and all the variables

15z-30=0

We move all terms containing z to the left, all other terms to the right

15z=30

z=30/15

z=2

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