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12z^2+66z+30=0
a = 12; b = 66; c = +30;
Δ = b2-4ac
Δ = 662-4·12·30
Δ = 2916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2916}=54$$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(66)-54}{2*12}=\frac{-120}{24} =-5 $$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(66)+54}{2*12}=\frac{-12}{24} =-1/2 $
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