12z-42=7z+18

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Solution for 12z-42=7z+18 equation: 



12z-42=7z+18

We move all terms to the left:

12z-42-(7z+18)=0

We get rid of parentheses

12z-7z-18-42=0

We add all the numbers together, and all the variables

5z-60=0

We move all terms containing z to the left, all other terms to the right

5z=60

z=60/5

z=12

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