12z-(3z-1)-(2z-35)=7+58

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Solution for 12z-(3z-1)-(2z-35)=7+58 equation: 


Simplifying
12z + -1(3z + -1) + -1(2z + -35) = 7 + 58

Reorder the terms:
12z + -1(-1 + 3z) + -1(2z + -35) = 7 + 58
12z + (-1 * -1 + 3z * -1) + -1(2z + -35) = 7 + 58
12z + (1 + -3z) + -1(2z + -35) = 7 + 58

Reorder the terms:
12z + 1 + -3z + -1(-35 + 2z) = 7 + 58
12z + 1 + -3z + (-35 * -1 + 2z * -1) = 7 + 58
12z + 1 + -3z + (35 + -2z) = 7 + 58

Reorder the terms:
1 + 35 + 12z + -3z + -2z = 7 + 58

Combine like terms: 1 + 35 = 36
36 + 12z + -3z + -2z = 7 + 58

Combine like terms: 12z + -3z = 9z
36 + 9z + -2z = 7 + 58

Combine like terms: 9z + -2z = 7z
36 + 7z = 7 + 58

Combine like terms: 7 + 58 = 65
36 + 7z = 65

Solving
36 + 7z = 65

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-36' to each side of the equation.
36 + -36 + 7z = 65 + -36

Combine like terms: 36 + -36 = 0
0 + 7z = 65 + -36
7z = 65 + -36

Combine like terms: 65 + -36 = 29
7z = 29

Divide each side by '7'.
z = 4.142857143

Simplifying
z = 4.142857143

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