12z+5=7z+41

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Solution for 12z+5=7z+41 equation: 



12z+5=7z+41

We move all terms to the left:

12z+5-(7z+41)=0

We get rid of parentheses

12z-7z-41+5=0

We add all the numbers together, and all the variables

5z-36=0

We move all terms containing z to the left, all other terms to the right

5z=36

z=36/5

z=7+1/5

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