12y=-8(10-y)

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Solution for 12y=-8(10-y) equation: 



12y=-8(10-y)

We move all terms to the left:

12y-(-8(10-y))=0

We add all the numbers together, and all the variables

12y-(-8(-1y+10))=0



We calculate terms in parentheses: -(-8(-1y+10)), so:

-8(-1y+10)

We multiply parentheses

8y-80

Back to the equation:

-(8y-80)



We get rid of parentheses

12y-8y+80=0

We add all the numbers together, and all the variables

4y+80=0

We move all terms containing y to the left, all other terms to the right

4y=-80

y=-80/4

y=-20

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