12y-3(y-3)=6y+8-(y-2)

Solution for 12y-3(y-3)=6y+8-(y-2) equation:

12y-3(y-3)=6y+8-(y-2)

We move all terms to the left:

12y-3(y-3)-(6y+8-(y-2))=0

We multiply parentheses

12y-3y-(6y+8-(y-2))+9=0


We calculate terms in parentheses: -(6y+8-(y-2)), so:

6y+8-(y-2)

determiningTheFunctionDomain
6y-(y-2)+8

We get rid of parentheses

6y-y+2+8

We add all the numbers together, and all the variables

5y+10

Back to the equation:

-(5y+10)


We add all the numbers together, and all the variables

9y-(5y+10)+9=0

We get rid of parentheses

9y-5y-10+9=0

We add all the numbers together, and all the variables

4y-1=0

We move all terms containing y to the left, all other terms to the right

4y=1

y=1/4

y=1/4