12y-10-2y=-10(y-3)

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Solution for 12y-10-2y=-10(y-3) equation: 



12y-10-2y=-10(y-3)

We move all terms to the left:

12y-10-2y-(-10(y-3))=0

We add all the numbers together, and all the variables

10y-(-10(y-3))-10=0



We calculate terms in parentheses: -(-10(y-3)), so:

-10(y-3)

We multiply parentheses

-10y+30

Back to the equation:

-(-10y+30)



We get rid of parentheses

10y+10y-30-10=0

We add all the numbers together, and all the variables

20y-40=0

We move all terms containing y to the left, all other terms to the right

20y=40

y=40/20

y=2

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