12y(y+3)=5(2y-7)

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Solution for 12y(y+3)=5(2y-7) equation: 



12y(y+3)=5(2y-7)

We move all terms to the left:

12y(y+3)-(5(2y-7))=0

We multiply parentheses

12y^2+36y-(5(2y-7))=0



We calculate terms in parentheses: -(5(2y-7)), so:

5(2y-7)

We multiply parentheses

10y-35

Back to the equation:

-(10y-35)



We get rid of parentheses

12y^2+36y-10y+35=0

We add all the numbers together, and all the variables

12y^2+26y+35=0

a = 12; b = 26; c = +35;
Δ = b2-4ac
Δ = 262-4·12·35
Δ = -1004
Delta is less than zero, so there is no solution for the equation

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