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12x^2=146
We move all terms to the left:
12x^2-(146)=0
a = 12; b = 0; c = -146;
Δ = b2-4ac
Δ = 02-4·12·(-146)
Δ = 7008
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{7008}=\sqrt{16*438}=\sqrt{16}*\sqrt{438}=4\sqrt{438}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{438}}{2*12}=\frac{0-4\sqrt{438}}{24} =-\frac{4\sqrt{438}}{24} =-\frac{\sqrt{438}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{438}}{2*12}=\frac{0+4\sqrt{438}}{24} =\frac{4\sqrt{438}}{24} =\frac{\sqrt{438}}{6} $
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