12x2-64x+64=0

Solution for 12x2-64x+64=0 equation:

12x^2-64x+64=0

a = 12; b = -64; c = +64;
Δ = b2-4ac
Δ = -642-4·12·64
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-64)-32}{2*12}=\frac{32}{24}
=1+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-64)+32}{2*12}=\frac{96}{24}
=4
$