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12x^2-63=-x
We move all terms to the left:
12x^2-63-(-x)=0
We add all the numbers together, and all the variables
12x^2-(-1x)-63=0
We get rid of parentheses
12x^2+1x-63=0
We add all the numbers together, and all the variables
12x^2+x-63=0
a = 12; b = 1; c = -63;
Δ = b2-4ac
Δ = 12-4·12·(-63)
Δ = 3025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3025}=55$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-55}{2*12}=\frac{-56}{24} =-2+1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+55}{2*12}=\frac{54}{24} =2+1/4 $
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