12x2-4=2(3x-2)

Solution for 12x2-4=2(3x-2) equation:

12x^2-4=2(3x-2)

We move all terms to the left:

12x^2-4-(2(3x-2))=0


We calculate terms in parentheses: -(2(3x-2)), so:

2(3x-2)

We multiply parentheses

6x-4

Back to the equation:

-(6x-4)


We get rid of parentheses

12x^2-6x+4-4=0

We add all the numbers together, and all the variables

12x^2-6x=0

a = 12; b = -6; c = 0;
Δ = b2-4ac
Δ = -62-4·12·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6}{2*12}=\frac{0}{24}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6}{2*12}=\frac{12}{24}
=1/2
$