12x2-41x+24=0

Solution for 12x2-41x+24=0 equation:

12x^2-41x+24=0

a = 12; b = -41; c = +24;
Δ = b2-4ac
Δ = -412-4·12·24
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{529}=23$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-41)-23}{2*12}=\frac{18}{24}
=3/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-41)+23}{2*12}=\frac{64}{24}
=2+2/3
$