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12x^2-143x+12=0
a = 12; b = -143; c = +12;
Δ = b2-4ac
Δ = -1432-4·12·12
Δ = 19873
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-143)-\sqrt{19873}}{2*12}=\frac{143-\sqrt{19873}}{24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-143)+\sqrt{19873}}{2*12}=\frac{143+\sqrt{19873}}{24} $
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