12x2-10x-12=0

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Solution for 12x2-10x-12=0 equation:



12x^2-10x-12=0
a = 12; b = -10; c = -12;
Δ = b2-4ac
Δ = -102-4·12·(-12)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-26}{2*12}=\frac{-16}{24} =-2/3 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+26}{2*12}=\frac{36}{24} =1+1/2 $

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