12x2-100x+28=0

Solution for 12x2-100x+28=0 equation:

12x^2-100x+28=0

a = 12; b = -100; c = +28;
Δ = b2-4ac
Δ = -1002-4·12·28
Δ = 8656
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{8656}=\sqrt{16*541}=\sqrt{16}*\sqrt{541}=4\sqrt{541}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-100)-4\sqrt{541}}{2*12}=\frac{100-4\sqrt{541}}{24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-100)+4\sqrt{541}}{2*12}=\frac{100+4\sqrt{541}}{24}
$