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12x^2+4=(x2+1)3
We move all terms to the left:
12x^2+4-((x2+1)3)=0
We add all the numbers together, and all the variables
12x^2-((+x^2+1)3)+4=0
We calculate terms in parentheses: -((+x^2+1)3), so:We get rid of parentheses
(+x^2+1)3
We multiply parentheses
3x^2+3
Back to the equation:
-(3x^2+3)
12x^2-3x^2-3+4=0
We add all the numbers together, and all the variables
9x^2+1=0
a = 9; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·9·1
Δ = -36
Delta is less than zero, so there is no solution for the equation
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