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12x^2+202.8x+623.7=0
a = 12; b = 202.8; c = +623.7;
Δ = b2-4ac
Δ = 202.82-4·12·623.7
Δ = 11190.24
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(202.8)-\sqrt{11190.24}}{2*12}=\frac{-202.8-\sqrt{11190.24}}{24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(202.8)+\sqrt{11190.24}}{2*12}=\frac{-202.8+\sqrt{11190.24}}{24} $
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