12x2+17x=7

Solution for 12x2+17x=7 equation:

12x^2+17x=7

We move all terms to the left:

12x^2+17x-(7)=0

a = 12; b = 17; c = -7;
Δ = b2-4ac
Δ = 172-4·12·(-7)
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-25}{2*12}=\frac{-42}{24}
=-1+3/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+25}{2*12}=\frac{8}{24}
=1/3
$