If it's not what You are looking for type in the equation solver your own equation and let us solve it.
12x^2+13x+3=0
a = 12; b = 13; c = +3;
Δ = b2-4ac
Δ = 132-4·12·3
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-5}{2*12}=\frac{-18}{24} =-3/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+5}{2*12}=\frac{-8}{24} =-1/3 $
| 10(2+x)-2(5-3x)=6-5x | | 2(1-x)-(3-x)=-1/3 | | 2(x+3)-4(1-3x)=10 | | 4+x/3-4x=1/5 | | -10(2-3x)=5(1-x) | | 52x–265x+25=0 | | 5^2x–26X5^x+25=0 | | 15=2(t+2)-3 | | a/2.7-1=10 | | 2q=-6+6 | | 14.2=5a | | 4n+2(n+4)=10 | | 12(y+8)=100 | | x/2.9=5.3 | | 10n+20=4n+40 | | 4(n-5)=35 | | 4x=4x+45 | | 10(n+4)=50+20 | | x=(3x+1)-(3x-5) | | 104+40=-5y+50 | | 5n-10=-2n+5 | | 8,5+3-2x=7=0,5+17 | | 10^(2a+3)=3 | | a-8.2=7.3 | | 8x=12x+24. | | 8z/4=0 | | -78=-42-a | | x/2-4/5+x/5=3x/10=1/5 | | 10y-6y-11=49.68 | | 8y-5y-11=38.77 | | 7y-5y-6=16.54 | | B={x|7x-1=13} |