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12x^2+-212x+630=0
We add all the numbers together, and all the variables
12x^2-212x=0
a = 12; b = -212; c = 0;
Δ = b2-4ac
Δ = -2122-4·12·0
Δ = 44944
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{44944}=212$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-212)-212}{2*12}=\frac{0}{24} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-212)+212}{2*12}=\frac{424}{24} =17+2/3 $
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