12x/3x+4x=0

Solution for 12x/3x+4x=0 equation:

12x/3x+4x=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R


We add all the numbers together, and all the variables

4x+12x/3x=0

We multiply all the terms by the denominator


4x*3x+12x=0

We add all the numbers together, and all the variables

12x+4x*3x=0

Wy multiply elements

12x^2+12x=0

a = 12; b = 12; c = 0;
Δ = b2-4ac
Δ = 122-4·12·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-12}{2*12}=\frac{-24}{24}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+12}{2*12}=\frac{0}{24}
=0
$