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12x-4/x=2
We move all terms to the left:
12x-4/x-(2)=0
Domain of the equation: x!=0We multiply all the terms by the denominator
x∈R
12x*x-2*x-4=0
We add all the numbers together, and all the variables
-2x+12x*x-4=0
Wy multiply elements
12x^2-2x-4=0
a = 12; b = -2; c = -4;
Δ = b2-4ac
Δ = -22-4·12·(-4)
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{196}=14$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-14}{2*12}=\frac{-12}{24} =-1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+14}{2*12}=\frac{16}{24} =2/3 $
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