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12x-4/3x-1=x
We move all terms to the left:
12x-4/3x-1-(x)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
11x-4/3x-1=0
We multiply all the terms by the denominator
11x*3x-1*3x-4=0
Wy multiply elements
33x^2-3x-4=0
a = 33; b = -3; c = -4;
Δ = b2-4ac
Δ = -32-4·33·(-4)
Δ = 537
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{537}}{2*33}=\frac{3-\sqrt{537}}{66} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{537}}{2*33}=\frac{3+\sqrt{537}}{66} $
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