12x-4-(8+3)+(7x-2)=68

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Solution for 12x-4-(8+3)+(7x-2)=68 equation: 



12x-4-(8+3)+(7x-2)=68

We move all terms to the left:

12x-4-(8+3)+(7x-2)-(68)=0

determiningTheFunctionDomain
12x+(7x-2)-4-68-(8+3)=0

We add all the numbers together, and all the variables

12x+(7x-2)-4-68-11=0

We add all the numbers together, and all the variables

12x+(7x-2)-83=0

We get rid of parentheses

12x+7x-2-83=0

We add all the numbers together, and all the variables

19x-85=0

We move all terms containing x to the left, all other terms to the right

19x=85

x=85/19

x=4+9/19

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