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12x-4(2x-10)=6-(x+3)
We move all terms to the left:
12x-4(2x-10)-(6-(x+3))=0
We multiply parentheses
12x-8x-(6-(x+3))+40=0
We calculate terms in parentheses: -(6-(x+3)), so:We add all the numbers together, and all the variables
6-(x+3)
determiningTheFunctionDomain -(x+3)+6
We get rid of parentheses
-x-3+6
We add all the numbers together, and all the variables
-1x+3
Back to the equation:
-(-1x+3)
4x-(-1x+3)+40=0
We get rid of parentheses
4x+1x-3+40=0
We add all the numbers together, and all the variables
5x+37=0
We move all terms containing x to the left, all other terms to the right
5x=-37
x=-37/5
x=-7+2/5
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