12x-4(2-x)=8(2x-3)+16

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Solution for 12x-4(2-x)=8(2x-3)+16 equation: 


Simplifying
12x + -4(2 + -1x) = 8(2x + -3) + 16
12x + (2 * -4 + -1x * -4) = 8(2x + -3) + 16
12x + (-8 + 4x) = 8(2x + -3) + 16

Reorder the terms:
-8 + 12x + 4x = 8(2x + -3) + 16

Combine like terms: 12x + 4x = 16x
-8 + 16x = 8(2x + -3) + 16

Reorder the terms:
-8 + 16x = 8(-3 + 2x) + 16
-8 + 16x = (-3 * 8 + 2x * 8) + 16
-8 + 16x = (-24 + 16x) + 16

Reorder the terms:
-8 + 16x = -24 + 16 + 16x

Combine like terms: -24 + 16 = -8
-8 + 16x = -8 + 16x

Add '8' to each side of the equation.
-8 + 8 + 16x = -8 + 8 + 16x

Combine like terms: -8 + 8 = 0
0 + 16x = -8 + 8 + 16x
16x = -8 + 8 + 16x

Combine like terms: -8 + 8 = 0
16x = 0 + 16x
16x = 16x

Add '-16x' to each side of the equation.
16x + -16x = 16x + -16x

Combine like terms: 16x + -16x = 0
0 = 16x + -16x

Combine like terms: 16x + -16x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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