12x-2(4x)+4-(1-x)=3(x+2)-4(4x-2)+16

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Solution for 12x-2(4x)+4-(1-x)=3(x+2)-4(4x-2)+16 equation: 



12x-2(4x)+4-(1-x)=3(x+2)-4(4x-2)+16

We move all terms to the left:

12x-2(4x)+4-(1-x)-(3(x+2)-4(4x-2)+16)=0

We add all the numbers together, and all the variables

12x-24x-(-1x+1)-(3(x+2)-4(4x-2)+16)+4=0

We add all the numbers together, and all the variables

-12x-(-1x+1)-(3(x+2)-4(4x-2)+16)+4=0

We get rid of parentheses

-12x+1x-(3(x+2)-4(4x-2)+16)-1+4=0



We calculate terms in parentheses: -(3(x+2)-4(4x-2)+16), so:

3(x+2)-4(4x-2)+16

We multiply parentheses

3x-16x+6+8+16

We add all the numbers together, and all the variables

-13x+30

Back to the equation:

-(-13x+30)



We add all the numbers together, and all the variables

-11x-(-13x+30)+3=0

We get rid of parentheses

-11x+13x-30+3=0

We add all the numbers together, and all the variables

2x-27=0

We move all terms containing x to the left, all other terms to the right

2x=27

x=27/2

x=13+1/2

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