12x-2(3-2x)=-38

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Solution for 12x-2(3-2x)=-38 equation: 



12x-2(3-2x)=-38

We move all terms to the left:

12x-2(3-2x)-(-38)=0

We add all the numbers together, and all the variables

12x-2(-2x+3)-(-38)=0

We add all the numbers together, and all the variables

12x-2(-2x+3)+38=0

We multiply parentheses

12x+4x-6+38=0

We add all the numbers together, and all the variables

16x+32=0

We move all terms containing x to the left, all other terms to the right

16x=-32

x=-32/16

x=-2

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