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12x-1=(9x+15)+(53)
We move all terms to the left:
12x-1-((9x+15)+(53))=0
We calculate terms in parentheses: -((9x+15)+53), so:We get rid of parentheses
(9x+15)+53
We get rid of parentheses
9x+15+53
We add all the numbers together, and all the variables
9x+68
Back to the equation:
-(9x+68)
12x-9x-68-1=0
We add all the numbers together, and all the variables
3x-69=0
We move all terms containing x to the left, all other terms to the right
3x=69
x=69/3
x=23
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