12x-110=3x+40+2x-10

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Solution for 12x-110=3x+40+2x-10 equation: 



12x-110=3x+40+2x-10

We move all terms to the left:

12x-110-(3x+40+2x-10)=0

We add all the numbers together, and all the variables

12x-(5x+30)-110=0

We get rid of parentheses

12x-5x-30-110=0

We add all the numbers together, and all the variables

7x-140=0

We move all terms containing x to the left, all other terms to the right

7x=140

x=140/7

x=20

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