12x+8(x+12)=8x-4(4x-10)

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Solution for 12x+8(x+12)=8x-4(4x-10) equation: 



12x+8(x+12)=8x-4(4x-10)

We move all terms to the left:

12x+8(x+12)-(8x-4(4x-10))=0

We multiply parentheses

12x+8x-(8x-4(4x-10))+96=0



We calculate terms in parentheses: -(8x-4(4x-10)), so:

8x-4(4x-10)

We multiply parentheses

8x-16x+40

We add all the numbers together, and all the variables

-8x+40

Back to the equation:

-(-8x+40)



We add all the numbers together, and all the variables

20x-(-8x+40)+96=0

We get rid of parentheses

20x+8x-40+96=0

We add all the numbers together, and all the variables

28x+56=0

We move all terms containing x to the left, all other terms to the right

28x=-56

x=-56/28

x=-2

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