12x+3(x-4)+6x=6x-57

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Solution for 12x+3(x-4)+6x=6x-57 equation: 



12x+3(x-4)+6x=6x-57

We move all terms to the left:

12x+3(x-4)+6x-(6x-57)=0

We add all the numbers together, and all the variables

18x+3(x-4)-(6x-57)=0

We multiply parentheses

18x+3x-(6x-57)-12=0

We get rid of parentheses

18x+3x-6x+57-12=0

We add all the numbers together, and all the variables

15x+45=0

We move all terms containing x to the left, all other terms to the right

15x=-45

x=-45/15

x=-3

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