12x+3(x+19)=40x+7

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Solution for 12x+3(x+19)=40x+7 equation: 



12x+3(x+19)=40x+7

We move all terms to the left:

12x+3(x+19)-(40x+7)=0

We multiply parentheses

12x+3x-(40x+7)+57=0

We get rid of parentheses

12x+3x-40x-7+57=0

We add all the numbers together, and all the variables

-25x+50=0

We move all terms containing x to the left, all other terms to the right

-25x=-50

x=-50/-25

x=+2

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