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12x+2(8-x)=3(2x-4)
We move all terms to the left:
12x+2(8-x)-(3(2x-4))=0
We add all the numbers together, and all the variables
12x+2(-1x+8)-(3(2x-4))=0
We multiply parentheses
12x-2x-(3(2x-4))+16=0
We calculate terms in parentheses: -(3(2x-4)), so:We add all the numbers together, and all the variables
3(2x-4)
We multiply parentheses
6x-12
Back to the equation:
-(6x-12)
10x-(6x-12)+16=0
We get rid of parentheses
10x-6x+12+16=0
We add all the numbers together, and all the variables
4x+28=0
We move all terms containing x to the left, all other terms to the right
4x=-28
x=-28/4
x=-7
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