12x(x-2)+3x=1/3(x+12)+10x

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Solution for 12x(x-2)+3x=1/3(x+12)+10x equation: 



12x(x-2)+3x=1/3(x+12)+10x

We move all terms to the left:

12x(x-2)+3x-(1/3(x+12)+10x)=0



Domain of the equation: 3(x+12)+10x)!=0

x∈R



We add all the numbers together, and all the variables

3x+12x(x-2)-(1/3(x+12)+10x)=0

We multiply parentheses

12x^2+3x-24x-(1/3(x+12)+10x)=0

We multiply all the terms by the denominator


12x^2*3(x+12)+10x)+3x*3(x+12)+10x)-24x*3(x+12)+10x)-(1=0

Wy multiply elements

36x^3(x+10x)+3x*3(x+12)+10x)-24x*3(x+12)+10x)-(1=0

We do not support expression: x^3(x

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