12x(x+3)=24(x-2)

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Solution for 12x(x+3)=24(x-2) equation: 



12x(x+3)=24(x-2)

We move all terms to the left:

12x(x+3)-(24(x-2))=0

We multiply parentheses

12x^2+36x-(24(x-2))=0



We calculate terms in parentheses: -(24(x-2)), so:

24(x-2)

We multiply parentheses

24x-48

Back to the equation:

-(24x-48)



We get rid of parentheses

12x^2+36x-24x+48=0

We add all the numbers together, and all the variables

12x^2+12x+48=0

a = 12; b = 12; c = +48;
Δ = b2-4ac
Δ = 122-4·12·48
Δ = -2160
Delta is less than zero, so there is no solution for the equation

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