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12x(x+11)=144
We move all terms to the left:
12x(x+11)-(144)=0
We multiply parentheses
12x^2+132x-144=0
a = 12; b = 132; c = -144;
Δ = b2-4ac
Δ = 1322-4·12·(-144)
Δ = 24336
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{24336}=156$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(132)-156}{2*12}=\frac{-288}{24} =-12 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(132)+156}{2*12}=\frac{24}{24} =1 $
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