12t2-147=0

Solution for 12t2-147=0 equation:

12t^2-147=0

a = 12; b = 0; c = -147;
Δ = b2-4ac
Δ = 02-4·12·(-147)
Δ = 7056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7056}=84$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-84}{2*12}=\frac{-84}{24}
=-3+1/2
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+84}{2*12}=\frac{84}{24}
=3+1/2
$