12t2-12t+3=0

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Solution for 12t2-12t+3=0 equation: 



12t^2-12t+3=0

a = 12; b = -12; c = +3;
Δ = b2-4ac
Δ = -122-4·12·3
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{12}{24}=1/2$

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