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12s^2=30
We move all terms to the left:
12s^2-(30)=0
a = 12; b = 0; c = -30;
Δ = b2-4ac
Δ = 02-4·12·(-30)
Δ = 1440
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1440}=\sqrt{144*10}=\sqrt{144}*\sqrt{10}=12\sqrt{10}$$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{10}}{2*12}=\frac{0-12\sqrt{10}}{24} =-\frac{12\sqrt{10}}{24} =-\frac{\sqrt{10}}{2} $$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{10}}{2*12}=\frac{0+12\sqrt{10}}{24} =\frac{12\sqrt{10}}{24} =\frac{\sqrt{10}}{2} $
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