12r-4(r+5)=5(2r-6)-2

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Solution for 12r-4(r+5)=5(2r-6)-2 equation: 



12r-4(r+5)=5(2r-6)-2

We move all terms to the left:

12r-4(r+5)-(5(2r-6)-2)=0

We multiply parentheses

12r-4r-(5(2r-6)-2)-20=0



We calculate terms in parentheses: -(5(2r-6)-2), so:

5(2r-6)-2

We multiply parentheses

10r-30-2

We add all the numbers together, and all the variables

10r-32

Back to the equation:

-(10r-32)



We add all the numbers together, and all the variables

8r-(10r-32)-20=0

We get rid of parentheses

8r-10r+32-20=0

We add all the numbers together, and all the variables

-2r+12=0

We move all terms containing r to the left, all other terms to the right

-2r=-12

r=-12/-2

r=+6

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