12r-4(r+4)=5(2r-3)-5

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Solution for 12r-4(r+4)=5(2r-3)-5 equation: 



12r-4(r+4)=5(2r-3)-5

We move all terms to the left:

12r-4(r+4)-(5(2r-3)-5)=0

We multiply parentheses

12r-4r-(5(2r-3)-5)-16=0



We calculate terms in parentheses: -(5(2r-3)-5), so:

5(2r-3)-5

We multiply parentheses

10r-15-5

We add all the numbers together, and all the variables

10r-20

Back to the equation:

-(10r-20)



We add all the numbers together, and all the variables

8r-(10r-20)-16=0

We get rid of parentheses

8r-10r+20-16=0

We add all the numbers together, and all the variables

-2r+4=0

We move all terms containing r to the left, all other terms to the right

-2r=-4

r=-4/-2

r=+2

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