12n2-38n+30n=2(3n-5)(2n-3)

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Solution for 12n2-38n+30n=2(3n-5)(2n-3) equation: 



12n^2-38n+30n=2(3n-5)(2n-3)

We move all terms to the left:

12n^2-38n+30n-(2(3n-5)(2n-3))=0

We add all the numbers together, and all the variables

12n^2-8n-(2(3n-5)(2n-3))=0

We multiply parentheses ..

12n^2-(2(+6n^2-9n-10n+15))-8n=0



We calculate terms in parentheses: -(2(+6n^2-9n-10n+15)), so:

2(+6n^2-9n-10n+15)

We multiply parentheses

12n^2-18n-20n+30

We add all the numbers together, and all the variables

12n^2-38n+30

Back to the equation:

-(12n^2-38n+30)



We add all the numbers together, and all the variables

12n^2-8n-(12n^2-38n+30)=0

We get rid of parentheses

12n^2-12n^2-8n+38n-30=0

We add all the numbers together, and all the variables

30n-30=0

We move all terms containing n to the left, all other terms to the right

30n=30

n=30/30

n=1

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