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12n^2+36n-216=0
a = 12; b = 36; c = -216;
Δ = b2-4ac
Δ = 362-4·12·(-216)
Δ = 11664
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{11664}=108$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-108}{2*12}=\frac{-144}{24} =-6 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+108}{2*12}=\frac{72}{24} =3 $
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